Tell me the average transaction amount for customers who have made more than 10 purchases within the last 90 days?

Question

Anonymous · Accepted Answer

SELECT
AVG(t.transaction_amount) AS average_transaction_amount
FROM
transactions t
WHERE
t.transaction_date >= DATE('now', '-90 days') -- For SQLite, use CURRENT_DATE -
INTERVAL '90 days' for PostgreSQL/MySQL
GROUP BY
t.customer_id
HAVING
COUNT(t.transaction_id) > 10

Anonymous · Answer

WITH 90_agg AS (

SELECT customer_id, count(*) t_count, avg(transaction_amount) avg_amt FROM
transactions WHERE transaction_date >= CURRENT_DATE() - 90 GROUP BY customer_id)

SELECT avg(avg_amt) FROM 90_agg WHERE t_count > 10;

Anonymous · Answer

select sum(amount)/count( distinct transaction_id) as avg_transaction
FROM transactions WHERE transaction_date >= CURRENT_DATE - INTERVAL '90 days'
GROUP BY customer_id
HAVING COUNT(transaction_id) > 10;

Anonymous · Answer

SELECT customer_id,
AVG(transaction_amount) AS avg_transaction_amount
FROM transactions WHERE transaction_date >= CURRENT_DATE - INTERVAL '90 days'
GROUP BY customer_id
HAVING COUNT(transaction_id) > 10;

Anonymous · Answer

Here is my made up answer

select cust_id,

avg(txn_amt) as avg_txn_amount

from table

where date >= current_date - 90

having count(*) > 10

Tell me the average transaction amount for customers who have made more than 10 purchases within the last 90 days?

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