In a pulse generator circuit featuring a 2-input NAND gate and a series of inverters causing a propagation delay, how would the output correspond to the input timing diagram?

Question

Anonymous · Accepted Answer

In a pulse generator circuit using a 2-input NAND gate and inverters with
propagation delays, the output pulse timing can be understood through the
following steps:

Understanding NAND Gate Behavior:

A 2-input NAND gate outputs a LOW (0) when both inputs are HIGH (1); otherwise,
it outputs HIGH (1).
Input Timing Diagram:

Let's denote the two inputs to the NAND gate as 
𝐴
A and 
𝐵
B.
Assume 
𝐴
A and 
𝐵
B have some input pulse timings (HIGH and LOW transitions) over time.
Propagation Delay of Inverters:

Inverters introduce a small delay in propagating the input signal to their
output. This delay could be denoted as 
𝜏
τ (tau).
Output Timing Diagram:

Initially, when both inputs 
𝐴
A and 
𝐵
B are LOW (0), the NAND gate output will be HIGH (1).
When one of the inputs (say 
𝐴
A) transitions from LOW to HIGH (0 to 1):
Due to the propagation delay 
𝜏
τ, the output of the corresponding inverter connected to 
𝐴
A will change with a delay.
This delay causes a brief moment where the NAND gate sees one input (from 
𝐵
B) as HIGH and the other (from 
𝐴
A) as still LOW (since 
𝐴
A is transitioning).
Therefore, the NAND gate output will momentarily go LOW (0) during this
transition period.
As 
𝐴
A completes its transition to HIGH, the output of the NAND gate will go HIGH (1)
again.
Output Pulse Generation:

The circuit can be designed such that the momentary LOW (0) output from the NAND
gate, caused by the input transition of 
𝐴
A, generates a pulse.
This pulse width is determined by the propagation delay 
𝜏
τ of the inverters.
Subsequent transitions of 
𝐵
B or 
𝐴
A will create additional pulses, depending on their timing relative to each
other and considering the propagation delays.
Summary:

The output of the pulse generator circuit will reflect the timing of the input
transitions, modified by the propagation delays of the inverters.
Each transition of the inputs 
𝐴
A and 
𝐵
B can potentially generate a brief pulse at the output of the NAND gate,
depending on their timing and the circuit design.

In a pulse generator circuit featuring a 2-input NAND gate and a series of inverters causing a propagation delay, how would the output correspond to the input timing diagram?

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